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6. A 55 kg student stands on a bathroom scale in an elevator of total mass 7.0 X 10 2 kg that is accelerating upward at 1.5 m/s 2. a) What is the tension in the cable that is pulling the elevator up? b) What would the student’s apparent weight be in the elevator (i.e. the reading on the scale)?

Assume that the positive y-axis points up. Q. Consider a man standing on a scale which is placed in an elevator. When the elevator is stationary, the scale reading is his weight W. Find S, the sca...

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The acceleration vs. time graph shows that the peak acceleration of the elevator was -1.400 m/s 2 at 9.1 s then goes at a constant velocity and decelerate to 1.288 m/s2 at 17.20s. In experiment 2, I rose the elevator up from the 2nd floor to the 16th floor.
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A person with mass of 55 kg is standing on a scale in an elevator. The elevator is moving up and accelerating at 1.5 m/s^2 for 3 seconds, then continues with constant speed. Find the scale reading a) before starting to move, b) when accelerating, c) when moving at constant speed?

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If the scale reading is equal to mg when the elevator is at rest, what is the scale reading while the elevator is accelerating downwards with a magnitude of a? Answer is terms of variables (m, a y, g). Q24. A person stands on a scale in an elevator. If the scale reads 600 N when that person is riding upward at a constant velocity of 4 m/s, what is the scale reading when the elevator is at rest? y = 0.7991x - 2

Nov 16, 2009 · There are 2 forces acting on you. (Complete the diagram.) Your weight pulls down with a force of 500 Newtons. The scale pushes up with a force of (11a) _____ (see below) Newtons. Since the elevator is moving with constant velocity, your acceleration is (11b) ____ m/s 2.
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Sep 25, 2017 · If an elevator is accelerating upward, then a mass's weight will increase, and the opposite is true for a descending elevator. With all of this in mind, along with the knowledge of how a MEMS accelerometer works, I decided to verify Newton's 2nd law and the theory of gravitation (on earth's surface, at least).

Calculate the scale reading: (a) if the elevator accelerates upward at a rate of 1. 20 m/s 2, and (b) if the elevator moves upward at a constant speed of 1 m/s. Figure 3: (a) The various forces acting when a person stands on a bathroom scale in an elevator.

If the object is moving along a straight line with a constant velocity it is in dynamic equilibrium. The requirement for either type of equilibrium is: Equilibrium Slide 6-27 The concept of equilibrium is essential for the engineering analysis of stationary objects such as bridges. On the way back down, while descending at constant velocity, the reading on the scale will be _____ 20 lbs. Greater than Less than Equal to A fisherman catches a 20 lb trout (mass=9.072 kg), and takes the trout in an elevator to the 78th floor to impress his girl friend, who is the CEO of a large accounting firm.

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What is the scale reading if the elevator is accelerating upward at 2 ft/s 2? F s - mg = ma F s = mg + ma = m(g + a) = (160 lb/32 ft/s 2)(32 + 2)ft/s 2 = 170 lb . 47. The object is a car that has driven off a cliff. (Ignore air resistance.) What is the scale reading if the elevator moves from the 3rd to the 5th floor (a) at constant velocity, (b) at a velocity which increases at the rate of 4.1 2 m s, (c) at a velocity which decreases at the rate of 3.2 2 m s? 6.51 F S is the force exerted by the scale on the student. It is the same as the scale reading because of the 3rd Law: the ... An the reading of the scale will correspond to the actual weight of the woman. Let us know consider the case when the elevator is accelerating upward; notice that the elevator velocity can still be upward or downward . The elevator can accelerate upward in two cases:

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The force of gravity acting on an object is also that object's weight. When you step on a scale, the scale reads how much gravity is acting on your body. The formula to determine weight is [source: Kurtus ]: weight = m * g. where m is an object's mass, and g is the acceleration due to gravity. straight lines imply constant velocity. curved lines imply acceleration. an object undergoing constant acceleration traces a portion of a parabola. average velocity is the slope of the straight line connecting the endpoints of a curve. instantaneous velocity is the slope of the line tangent to a curve at any point. To speed up To slow down To change direction Unit: Newton (SI system) Newton’s First Law The Law of Inertia. A body in motion stays in motion at constant velocity and a body at rest stays at rest unless acted upon by an external force. This law is commonly applied to the horizontal component of velocity, which is assumed not to

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World's largest library of math & science simulations. Gizmos are interactive math and science simulations for grades 3-12. Over 400 Gizmos aligned to the latest standards help educators bring powerful new learning experiences to the classroom. But now we have some velocity. We did that just for the sake of simplicity. Let's say this screen lasted for 1 second. So now our velocity is going to be 2 meters per second in the j direction, or in the upwards direction. And then let's say we do that for 10 seconds. So at least at the constant velocity, we travel for 20 meters.

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B3-CT62: PERSON IN AN ELEVATOR—SCALE READING A person who weighs 500 N is standing on a scale in an elevator. The elevator is identical in both cases. In both cases the elevator is moving at a constant speed, upward in Case A and downward in Case B. v = 3 m/s v = 3 m/s Starting up Constant v down Constant v up Slowing down Slowing up At rest At rest Analysis. 1. Identify the times in the elevator ride when the scale reading is normal. Describe the motion(s) at those times. In particular, is your velocity changing during those times--are you accelerating? 2. Identify the times in the elevator ride when the ...

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Apr 20, 2016 · As the elevator starts moving, the scale reads 90kg Is the elevator acceleration up or down, is the elevator moving up or down? Physics. A 1000kg elevator carries a maximum load of 800kg. A constant frictional force of 5000N retards the elevator's motion upward. What minimum power, in kilowatts, must the motor deliver to lift the fully loaded elevator at a constant

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2. Allow the roller to move up the inclined plane by adjusting the mass in the pan. Interpret the graph between W′ and sin θ where W′ is the mass in pan added to the mass of the pan required to allow the roller to move upward with constant velocity. 1. Jun 10, 2014 · An 80.0 kg passenger stands on a measuring scale in an elevator. The scale reading for the first 20.0 s are presented by the graph below. Use g = 10 m/s2 in the following calculations.

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Q. The man pictured has a true or at rest weight of 700N but the scale reading is 1000 N. The elevator must be ... A block having a mass of 2 kg is placed on a a spring scale located in an elevator that is moving downward. If the scale reading, which measures the force in the spring, is 20 N, determine the acceleration of the elevator. Neglect the mass of the scale. 3 . The 300-kg bar B, originally at rest, is being towed over a series of small rollers.

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Constant Velocity: The first motion diagram, shown in Fig. 1, is for an object moving at a constant speed toward the right. The motion diagram might represent the changing position of a car moving at constant speed along a straight highway. Each object (car) indicates the position of the object at a different time. What is the scale reading if the elevator is accelerating upward at 2 ft/s 2? F s - mg = ma F s = mg + ma = m(g + a) = (160 lb/32 ft/s 2)(32 + 2)ft/s 2 = 170 lb . 47. The object is a car that has driven off a cliff. (Ignore air resistance.)

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What will the scale read if the elevator is moving at a constant velocity????? N mg Snowman mass = 50 kg 6 F ma a 0 N mg 0 N mg 50kg u 9.8 N kg 0( N ) 490 (N) Scale reads 490(N) for constant velocity on the way up or way down (and when at rest) Nov 05, 2010 · Reading your dog posts is the highlight of any day -- I've been known to pull up your blog in-clinic to get some laughter during the day as I work on the clinical side of cancer research and days can be really tough.

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The velocity vs. time graph shows that the elevator started from rest and accelerated in the downward position reaching a peak speed of 0.820 m/s at 6.1 s, until it reached a constant velocity. When we reached the basement the graph shows that the elevator decelerated and came to a stop. As the elevator accelerating in upward direction, the tension acting on the body which hangs by a spring scale from the ceiling will be greater than the weight of the body. This tension will show in the reading of the spring scale and that will be greatest. This condition is equivalent to the elevator is descending with decreasing speed.

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scp1134 foundations of physics lab preparation preparation name: ho koh student number: 10362372 lab day and time: wednesday class cohort: red blue you have set = velocity of the Passenger relative to the Ground v PG = v PT + v TG Inner subscripts disappear You are running toward the right at 5 m/s toward an elevator that is moving up at 2 m/s. Relative to you, the direction and magnitude of the elevator’s velocity are A. down and to the right, less than 2 m/s. B. up and to the left, less than 2 m/s. Oct 22, 2007 · Since momentum is mass times velocity, the faster you’re going when you hit the ground, the more force you will feel, and the more it will hurt. If the elevator has been falling for a while, then it’s probably moving very fast. If you jump up, then you’ll change your velocity just a little bit.

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6. A 55 kg student stands on a bathroom scale in an elevator of total mass 7.0 X 10 2 kg that is accelerating upward at 1.5 m/s 2. a) What is the tension in the cable that is pulling the elevator up? b) What would the student’s apparent weight be in the elevator (i.e. the reading on the scale)? If the object is moving along a straight line with a constant velocity it is in dynamic equilibrium. The requirement for either type of equilibrium is: Equilibrium Slide 6-27 The concept of equilibrium is essential for the engineering analysis of stationary objects such as bridges.

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A {eq}62\, kg {/eq} woman is standing on a scale while riding in an elevator, the elevator continues to move up with a constant velocity. What is the reading on the scale? Whilst the absurdity doesn't scale the heights of Sunny's teeth vs sword duel in book 4 we do get to see Sunny scale the heights Currently I'm reading book 12 of 13 to Celyn. The story formula is eroding by book 6 and some welcome variety / twists are introduced.

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50. A person of weight 480 N stands on a scale in an elevator. What will the scale be reading when the elevator is accelerating downward at 4.00 m/s2? 51. An object is on a frictionless inclined plane. The plane is inclined at an angle of 30° with the horizontal. What is the object's acceleration? 52.

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Nov 30, 2020 · Since you have constant drilling speed, and a typical cross section across the human body is 25 cm, you will be getting that force over about 1/3 of a millisecond. This gives an impulse of 0.06 N s. A 75 kg human would be sent moving at the blistering speed of 0.08 mm/s (about 2 minutes to move one centimeter). a. The elevator is moving up at a constant speed. Since the elevator is moving at a constant speed the acceleration is zero. The weight read from the scale would be the same if the elevator was stopped. or was stopped. 2 72.2 0 N ? m kg a m s F = = = ( ) ( 708 ) (72.2 )0 2 N g N F F F ma F F N kg m s ∑ = + = ∑ = + − = N ( 708 ) 0 N 708 F F N N F N ∑ = + − = = b. The elevator is moving down at a constant speed.

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The basics are that an object which has no net force on it moves with a constant velocity (Newton's first law). To change the velocity (accelerate or decelerate) you must push or pull on it (exert a force) (Newton's second law). In equation form, Newton's second law may be stated F=ma where this says force=mass times acceleration. v constant F 0 For a single particle: 0. Newton’s first law is a particular case of Newton’s second law, with a = 0. 1. This law holds only in “inertial frames”. 2. An observing frame moving with a constant velocity

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c. 40 N up d. We are not able to say. 13. A child stands on a bathroom scale while riding in an elevator. The child's weight when the elevator is not moving is 100 pounds. What does the scale read when the elevator accelerates upward while traveling downward? a. greater than 100 lbs

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A person with mass of 55 kg is standing on a scale in an elevator. The elevator is moving up and accelerating at 1.5 m/s^2 for 3 seconds, then continues with constant speed. Find the scale reading a) before starting to move, b) when accelerating, c) when moving at constant speed? Dec 07, 2019 · At its initial position, the cylinder has no kinetic energy because it's not moving. Instead, all of its energy is potential energy, meaning its energy can be written as E = mgh with a mass m, gravitational constant g = 9.8 m/s 2 and height h.

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Then the elevator moves at a constant velocity for a time interval 4T. Finally the elevator brakes with an acceleration of magnitude a, (the same magnitude as the initial acceleration), for a time interval T until stopping at the sixth oor. (a) Make a sketch of the velocity v(t) of the elevator as it travels to the sixth oor.

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A) objects moving with an initial speed relative to a given frame of reference eventually come to rest relative to the reference frame. B) whether an object is at rest or is moving with constant velocity depends on the inertial reference frame in which the object is observed. C) rest is the most natural state of motion.

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If the rope does not move, the tension in it is A) 18 kN B) 9.0 kN C) 44 kN D) 4.5 kN E) 0.46 kN 2. You are riding an elevator that is accelerating upward at 2.20 m/s2. You have a spring balance accurately calibrated in newtons. When you hang a mass of 10.0 kg on the balance, the reading of the balance is

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Nov 01, 2018 · C)moving upward at constant speed D)moving downward at constant speed 12.A man standing on a scale in an elevator notices that the scale reads 30 newtons greater than his normal weight. Which type of movement of the elevator could cause this greater-than-normal reading? A)a child gaining speed while sliding down a slide B)a woman accelerating ... According to A, the apple has momentum and velocity that is not zero (p > 0, v = v 1 > 0). However if an observer B is inside the elevator, the apple does not appear to moving from their perspective, so B thinks the apple has zero momentum and zero velocity (p = v = 0) .

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For example, an FMCW lidar sensor may only receive a few returns on an object 300m away, but if those hits give a velocity value of interest (e.g., moving towards the vehicle at >70 mph) our ...

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When the elevator slows to a stop at the 10th floor, the scale reading drops to 735 N for 2 seconds while coming to a stop. (a) Explain why the apparent weight of the student increased at the beginning of the motion. (b) Draw the free body diagram for the student while the student is accelerating upward, then moving at a constant velocity, and ...

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Elevator An elevator is being lowered at a constant speed by a steel cable attached to an electric motor. Which statement is correct? B. The cable does positive work on the elevator, and the elevator does negative work on the cable. C. The cable does negative work on the elevator, and the elevator does positive work on the cable. D. The combined system of you + elevator has two forces, a combined force of gravity and the tension in the cable. Consider the normal force acting on you from the elevator: N = mg if the elevator is at rest or moving at constant velocity N = mg + ma if the elevator has an upward acceleration N = mg - ma if the elevator has a downward acceleration W = m*g = 75*9.81 N If the elevator is moving at a constant velocity, then the elevator can again be treated as an inertial frame, because it is not accelerating, and the weight measured is the...

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Scale Find S, the scale reading when the elevator is moving upward with acceleration a = 1 3 g. 1. S = 2 3 W 2. S = 3 4 W 3. S = 1 2 W 4. S = 4 3 W correct 5. S = 5 3 W 6. S = 1 3 W 7. S = 2 W 8. S = 5 4 W 9. S = 3 2 W 10. S = 0 m/s 2 Explanation: We consider the forces acting on the man. Taking up (ˆ ) as positive, we know that m g acts on the man in the downward (− ˆ ) di-rection. Now the elevator is moving downward with a velocity of v = -2.9 m/s but . asked by Austin on October 14, 2018 Help Physics A child with a mass of 39 kg stands on a spring scale inside an elevator. For each of the scenarios below, draw a force diagram of the forces acting on the child and calculate the reading of the scale in newtons.

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6. A man weighs 900 Newtons standing on a scale in a stationary elevator. If some time later the reading on the scale is 1200 Newtons the elevator must be moving with? Constant acceleration downward Constant speed downward Constant acceleration upward Constant speed upward; 7. Net force F causes mass m 1 to accelerate at rate a 1.

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If the rope does not move, the tension in it is A) 18 kN B) 9.0 kN C) 44 kN D) 4.5 kN E) 0.46 kN 2. You are riding an elevator that is accelerating upward at 2.20 m/s2. You have a spring balance accurately calibrated in newtons. When you hang a mass of 10.0 kg on the balance, the reading of the balance is Tension in an elevator cable An elevator and its load have a total mass of 800 kg. The elevator is originally moving downward at 10.0 m/s; it slows to a stop with constant acceleration in a distance of 25.0 m. Find the tension T in the supporting cable while the elevator is being brought to a rest.

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An 80 kg woman stands on a scale in an elevator. When the elevator starts to move, the scale reads 700N. (a) Is the elevator moving upward or downward? (b) Is its velocity constant? If so, what is it? If not, what is the elevator's acceleration? Draw the free-body diagram before analyzing the motion. 7-90 , e)eucHor (n an/ ape app is SCQle. 50 ... 6. A man weighs 900 Newtons standing on a scale in a stationary elevator. If some time later the reading on the scale is 1200 Newtons the elevator must be moving with? Constant acceleration downward Constant speed downward Constant acceleration upward Constant speed upward; 7. Net force F causes mass m 1 to accelerate at rate a 1. The Earth-Moon frame rotates with an angular velocity!= r G(M+ m) D3: (4) Thus the centrifugal acceleration is a cent(x) = (x c:o:m: x)!2 = G(M+ m) D3 mD M+ m x : (5) The stationary Spaceline feels no Coriolis forces. Pay-loads moving along it will, although at speeds of up to 0:01c, the resulting bowing of the cable is negligible.

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In fact, a negative acceleration will increase a negative velocity. For example, the train moving to the left in Figure 2.22 is sped up by an acceleration to the left. In that case, both v and a are negative. The plus and minus signs give the directions of the accelerations. If acceleration has the same sign as the velocity, the object is ... scp1134 foundations of physics lab preparation preparation name: ho koh student number: 10362372 lab day and time: wednesday class cohort: red blue you have set

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Sep 25, 2017 · If an elevator is accelerating upward, then a mass's weight will increase, and the opposite is true for a descending elevator. With all of this in mind, along with the knowledge of how a MEMS accelerometer works, I decided to verify Newton's 2nd law and the theory of gravitation (on earth's surface, at least). Linear Acceleration An object moving along a straight line with constant speed has constant velocity and zero acceleration A car that can go from 0 to 60 km/hour (1 km/minute) in 1 minute has a linear acceleration of 1 km/minute2 An object falling off the roof (on Earth) experiences a constant linear acceleration downward (g = 9.8 m/sec2). Discuss (like a physics student would !). 3) Consider a complete downward trip on the elevator and discuss how you (your body) felt at the different parts of the trip, and why. Write a good summary, as always, at the end of this lab. ￹ Elevator motion scenario Velocity & acceleration directions Bath scale reading and related calcs. True wt=____lb

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up down. 3. An elevator starts from rest at the 100th floor of the Empire State Building and speeds up to a constant speed as it descends, with no stops, until it slows down to a stop at the ground floor (Draw this one vertically as well, since the motion is vertical). 4.

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